Method 1
Assuming the first element of the array to be the largest and second element to be the next largest value and then swapping with the next element if the next is larger
#include <stdio.h>
#define MAX 4
void main()
{
int array[MAX], i, largest1, largest2, temp;
printf("Enter %d integer numbers \n", MAX);
for (i = 0; i < MAX; i++)
{
scanf("%d", &array[i]);
}
printf("Input integer are \n");
for (i = 0; i < MAX; i++)
{
printf("%5d", array[i]);
}
printf("\n");
/* assume first element of array is the first larges t*/
largest1 = array[0];
/* assume first element of array is the second largest */
largest2 = array[1];
if (largest1 < largest2)
{
temp = largest1;
largest1 = largest2;
largest2 = temp;
}
for (i = 2; i < 4; i++)
{
if (array[i] >= largest1)
{
largest2 = largest1;
largest1 = array[i];
}
else if (array[i] > largest2)
{
largest2 = array[i];
}
}
printf("n%d is the first largest \n", largest1);
printf("%d is the second largest \n", largest2);
printf("\n Average of %d and %d = %d \n", largest1, largest2,
(largest1 + largest2) / 2);
}Output
Enter 4 integer numbers
80
23
79
58
Input interer are
80 23 79 58
80 is the first largest
79 is the second largest
Average of 80 and 79 = 79